(1/1-100x)^2=1+290x

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Solution for (1/1-100x)^2=1+290x equation: 



(1/1-100x)^2=1+290x

We move all terms to the left:

(1/1-100x)^2-(1+290x)=0



Domain of the equation: 1-100x)^2!=0

We move all terms containing x to the left, all other terms to the right

-100x)^2!=-1

x!=-1/1

x!=-1

x∈R



We add all the numbers together, and all the variables

(-100x)^2-(290x+1)=0

We get rid of parentheses

(-100x)^2-290x-1=0

We add all the numbers together, and all the variables

-290x+(-100x)^2-1=0

We move all terms containing x to the left, all other terms to the right

-290x+(-100x)^2=1

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